Re: removing an array element

Erik Price wrote:

what function is used to remove an array element from an array? Like array_pop(), except one by which I can refer to the element by its associative index rather than just the last element of the array.

For more detail with what I'm doing, I have two versions of a <select> listbox -- one that includes an <option> with selected="yes" (if the user is calling this page from submitting a form). The other version is for users who are NOT calling this page from submitting a form, i.e. for the first time. I would like, in the first version (if ($formfilled)), to REMOVE the element $temprow['div_name'] from the array $temprow so that it doesn't appear a second time (in the WHILE loop), since it has already been echoed above the WHILE loop. Is this even possible?

I would do it another way. say you have all the possible choices in an array that come out of a database, and ypou want, if the user already selected one, this one to be selected, right? Then i would set the selected atribute only if the value out of the database is the same as the one submitted by the form: like this (omitting the surrounding html): $query= "select distinct * from sometable"; $result=mysql_query($query); // the select field is named selectfield, echo "<form name=\"myform\" action=\"$PHP_SELF\" Method=\"post\">"; echo "<select name=\"selectfield\">"; // the variable $selectfield is, if set the value submitted by the form $selectfield = $_POST["selectfield"]; while ($row=mysql_fetch_array($result)){ echo "<option"; // assuming the second element of this array holds your // choices then if($selectfield == $row[1]){ echo " selected"; } echo ">" . $row[1] . "</option>\n"; } echo "</select>" echo "<input type=\"submit\">\n"; echo "</form>"; i think this is a more straightforward solution for your problem... henning