CONTINUE - variable problem - help!

hi again! I tried it but it desn't give me any result back. It dosn't print any error message but it desn't print my result either. this is how I place the code: echo "...some html code..."; $row["somename_$var"]; echo "...the continuation of the html code"; thanks! Stefan Rusterholz wrote: > > Hi! > > > > I 'm trying not to hard code my php coding and I'm trying to pass a > > variable name into the $row[coloumname_$variable]; > $row["columname_$variable"] should do it. > $row[constant] is threaten as constant which is normally not the programmers > intention (set_error_reporting(0) and you'll see PHP's complaints about it) > so PHP converts it to $row['constant']. > You may now understand, that PHP "translates" your code to > $row['coloumname_$variable'] whre $variable is a string and not a variable. > > I hope, I could express myself understandable :) > best regards > Stefan Rusterholz > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net