Re: Variable referencing/substitution

See the manual on references: http://php.he.net/manual/en/language.references.php $vNames[1] = &$variable Fred Gaylen Fraley <gfraley5@earthlink.net> wrote in message news:20020120044347.27790.qmail@pb1.pair.com... > How can this be done? > > If I have the name of a variable that is stored in an array, how do I use > the stored value to represent the actual variable? > > Example: > > $variable = "old value"; > $vNames[1] = '$variable'; //literal $variable > > I want to say $vNames[1] = "new value"; /and have $variable actually > change. > > How? > > -- > Gaylen > gfraley5@earthlink.net > Home http://www.gaylenandmargie.com/ > PHP KISGB v3.1 Guest Book > http://www.gaylenandmargie.com/phpwebsite/ > > >