Re: variable function call (Re: [PHP] unset a function?)

Hello, > $func = "make_" . $wat; > $temp = $$func($this); I think one $. $func = "make_" . $wat; $temp = $func($this); will work Bas Op donderdag 31 januari 2002 12:17, schreef u: > Hoi Bas, > > $func = "make_" . $wat; > > $temp = $$func($this); > > bvr. > > On Thu, 31 Jan 2002 11:55:12 +0100, Bas Jobsen wrote: > >Hello, > > > >> Thanks all. I will rename the second function. > > > >Now if have: > > > >if($wat=="naam")$temp=make_naam($this); > >else if($wat=="anderenaam")$temp=make_anderenaam($this); > >//etc.. > > > >But i would prefer something like > >$temp=make_$wat($this); > > > >How can i do this? > > > >Tnx, > > > >Bas > > > >-- > >PHP General Mailing List (http://www.php.net/) > >To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > >For additional commands, e-mail: php-general-help@lists.php.net > >To contact the list administrators, e-mail: php-list-admin@lists.php.net