RE: [PHP] Making your include files invisible (header() in if loop)

I don't know if this is related but header() must be called before any actual output is sent. One way to resolve this is to use the ob_start() tag at the start of the code, this turns output buffering on. Mind you I am no expert and stand ready to be corected and berated. Peter I wanted to hide the existance of my include files by making them 'invisible': give a 404 error when requested. This worked, but the files that were including were obviously 404ing too. So I decided to use $PHP_SELF and check whether the script's PHP_SELF was it's filename, which would mean that it was being accessed directly, as opposed to being included. I tried this code: (include.php) <? $string = "include"; $container = "$PHP_SELF"; if(strstr($container,$string)) { header("HTTP/1.0 404 not found"); exit; } ?> at the top of the include files, but it wasn't working. Change the header() to an echo and test it. It echoed. So it's a problem with the header(). I tried this: <? header("HTTP/1.0 404 Not Found"); ?> and it worked perfectly. Can header() not be in an if loop or something like that? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net