Re: Adding 6 digits to a str?

like this: $digit = 122; $digits = sprintf ("%08d", $digit); print $digits; Greets, Edward ----- Original Message ----- From: "Jeff Sheltren" <sheltren@cox.net> To: "Andy" <news.letters@gmx.de>; <php-general@lists.php.net> Sent: Saturday, February 02, 2002 6:41 PM Subject: Re: [PHP] Adding 6 digits to a str? > Why is it that you want to represent an int with leading 0's? Is it just > to print it out that way? If that is the case, then you can use the printf > function for formatted printing. > > > Jeff > > At 10:53 AM 2/2/2002 +0100, Andy wrote: > >Hi guys, > > > >I am trying to force a int to be 8 digits. If it is only 3 dig filling the > >first ones with 0. > > > >Anyhow I tryed it with type casting, but it does not matter what I try, I > >always get an addition. > > > >E.g: > > $member_id is: 136 > > should be: 00000136 > > > >Here is the code, which is still returning 136: > > > > for($i=0;$i<count($member_id);$i++){ > > $length = strlen($member_id[$i]); > > > > settype ($member_id[$i], "string"); > > $zero = '0'; > > settype ($zero, "string"); > > > > $member_id[$i] = $zero + $member_id[$i]; > > echo $member_id[$i]; > > } > > > >Does anybody know how to solve this thing?? > > > >Thanx Andy > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >