Re: Easy Question -- Show/ Hide text based on output of query

From: Date: Tue, 05 Feb 2002 17:52:06 +0000
Subject: Re: Easy Question -- Show/ Hide text based on output of query
References: 1  Groups: php.general 
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On Wednesday 06 February 2002 00:03, Edward R. Bailey wrote: > Hi, > > I am working on a page the displays the output of a query in a table and > I only want to show the field labels that have corresponding output from > the database. I am only really concerned with the last label in the > table. > > The label is called "Notes" and the corresponding field in the database > is "memberNotes" > > So I wrote the following script where I think I am saying if memberNotes > returns any value then print the output of $notes in the table cell > where it is called, but nothing happens and the output of $notes is not > displayed regardless whether "memberNotes" has any output. > > <?php If ($memberNotes =='1') { What is $memberNotes supposed to contain? If it is supposed to contain notes on members then surely it can't be '1' all the time? I think you probably want: if ($memberNotes) { ... hth -- Jason Wong -> Gremlins Associates -> www.gremlins.com.hk /* Where is John Carson now that we need him? -- RLG */

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