Re: how a function 'return' statement works
| From: | Gerhard Hoogterp | Date: | Wed, 13 Feb 2002 22:18:32 +0000 |
| Subject: | Re: how a function 'return' statement works | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-84672@lists.php.net to get a copy of this message | ||
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On Wednesday 13 February 2002 22:55, Erik Price wrote:
> Can anyone give my puny mind an explanation as to why the following
> function only returns the value "Array" ?
>
> # ===============================================================
> # get_current_page_name()
> # ---------------------------------------------------------------
> # Returns the current document
> # Arguments
> # -----------
> # no arguments
> # ===============================================================
>
> function get_current_page_name()
> {
> $current_page_name = explode("/", $_SERVER['PHP_SELF']);
> $current_page_name = array_slice($current_page_name, -1);
> return $current_page_name;
> }
>
from the manual:
array array_slice ( array array, int offset [, int length])
array in, array out.. it wouldn't suprice me if when you changed the return
into
return $current_page_name.'';
it would become a string again.
Gerhard
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