RE: [PHP] php - assigning date variables

From: Date: Tue, 26 Feb 2002 15:50:40 +0000
Subject: RE: [PHP] php - assigning date variables
Groups: php.general 
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I think you can't achieve this with the example you've provided. Perhaps something like this will work: query = ""; mysql_query("SELECT * FROM table ". $query ); query = "WHERE date = '2001-01-01'"; // This should return all rows with 2001-01-01 as date. query = "WHERE date > '1995-01-01'"; // All items newer than 1995-01-01. query = "WHERE date < '1995-01-01'"; // All items older than 1995-01-01. query = "WHERE date > '1995-01-01' AND date < '1998-01-01'"; // All items between 1995-01-01 and 1998-01-01. Hope this helps /Joakim > -----Original Message----- > From: Craig Westerman [mailto:westerman@chanuteks.com] > Sent: Monday, February 25, 2002 7:34 PM > To: php-general@lists.php.net > Subject: [PHP] php - assigning date variables > > > $query = "" > mysql_query("SELECT * FROM table WHERE date LIKE '%". $query > ."%'"); > // returns all items in database > > > $query = "2001-01-01" > mysql_query("SELECT * FROM table WHERE date LIKE '%". $query > ."%'"); > // returns all rows that have 2001-01-01 as the date > > > What is proper way to define a variable to include all dates > newer than > 1995-01-01? > $query = "???" > > What is proper way to define a variable to include all dates > older than > 1995-01-01? > $query = "???" > > What is proper way to define a variable to include all dates between > 1995-01-01 and 1998-12-31? > $query = "???" > > > Everything I tried gives me a error. This has to be simple, > but I must be > overlooking something. Where would I find the answer? > > Thanks > > Craig ><> > westerman@chanuteks.com > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

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