Re: dynamic pulldown list generation help

I got this to work, it list all file (type f) in the current directory, you can extend it further. $ls = split("\n", rtrim (ls)); print "<select name=\"test\">"; while (list ($key, $value) = each ($ls)) { if (is_file ($value)) print "<option value=\"$key\">$value</option>\n"; } print "</select>"; =S. On Tue, 26 Feb 2002, Andrew Slezak wrote: > Basically I am setting ls > array(). I want each item to be an option in > the array. I have have scoured for some time now and this is what I have > come up with, but it is not populating each file as an <option>? The select > box is just empty. I know this is an array because I have tested with > print_r. Stuck! > > Can someone tell me what I am doing wrong? > ------------------------------------------------ > <? > $shell_scripts=`ls -1 /sm_scripts|grep -v backup|grep -v outmail|grep -v > c_`; > $shell_scripts=rtrim($shell_scripts); > $arr1=split("\n", "$shell_scripts"); > //print_r($arr1); > > > echo "<p>"; > echo "<select name=test>"; > function generate_option_list($arr1, $set) { > reset($arr1); > while (list($key,$value) = each($arr1) ) { > {$var.="<option value='$key'>$value</option>";} > } return $var; > } > > echo "</select>"; > ------------------------------------------------ > ?> > > TIA, > Andy > > >