Re: User accounts

From: Date: Thu, 07 Mar 2002 22:44:09 +0000
Subject: Re: User accounts
References: 1  Groups: php.general 
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Here's a little piece of code that gives me a weird problem: <?php if (!$logout) { if ($_SESSION['loggedin']) { unset($_SESSION['loggedin']); } } ?> I have the session started and everything, but it gives me the following error. Warning: Undefined variable: logout in c:\inetpub\wwwroot\uslogin.php on line 13 I've seen this used on several examples. I know that if I just use empty($logout) then it'll work ok, but I just wanted to know why it's used in so many examples but doesn't work in my code. Is there some setting that I have set wrong or something? Thanks, Dave "David Johansen" <daveisfera@yahoo.com> wrote in message news:20020307194743.11185.qmail@pb1.pair.com... > I'm new to this php thing and I would like to set up a web page were the > users can login and edit their preferences and all that stuff. I have the > basic login stuff worked out and I was passing the username and password as > a hidden input in the form, but then the password can be seen with view > source. I know that there's a better way to do this, so could someone point > me to a good tutorial or example on how I could make it so that the user > could login and logout and then I wouldn't need to be passing the password > all around like this. Thanks, > Dave > >

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