Re: need help converting code to more efficient loop
| From: | Jason Wong | Date: | Sun, 10 Mar 2002 04:33:14 +0000 |
| Subject: | Re: need help converting code to more efficient loop | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-87896@lists.php.net to get a copy of this message | ||
On Saturday 09 March 2002 18:08, Timothy J. Luoma wrote:
> Hello! I am trying to reduce the size of the code below, which I believe
> can be simplified.
>
> I checked the 'for' entry in the manual as well as googling for some
> similar code, but did not have any luck.
>
> Here is what I have:
>
>
> $ICON_COUNT="0";
>
> if ($SHOW_WAI_ICON != "no")
> {
> $ICON_COUNT++ ;
> }
>
> if ($SHOW_BOBBY508_ICON != "no")
> {
> $ICON_COUNT++ ;
> }
>
> if ($SHOW_W3_ICON != "no")
> {
> $ICON_COUNT++ ;
> }
>
> if ($SHOW_CSS_ICON != "no")
> {
> $ICON_COUNT++ ;
> }
>
>
> Now I would like to make that a 'for' loop, but I'm not sure how to do it
> in PHP.
>
> In case it is not clear what I am trying to do, this is what I would do if
> PHP syntax were like bash:
>
> variables="SHOW_CSS_ICON SHOW_W3_ICON SHOW_BOBBY508_ICON SHOW_WAI_ICON"
>
> for i in $variables
> do
>
> if [ "$i" != "no" ]
> then
> #increment icon_count here
> fi
>
> done
>
>
> I'm just not sure about the nested syntax in PHP.
$doo = array("SHOW_CSS_ICON", "SHOW_W3_ICON");
foreach($doo as $dah) {
if (${$dah} != "no") {
$ICON_COUNT++;
}
}
*** Untested, use with caution! ***
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
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