Re: 'undef' as an argument value

function foo ($arg1_required, $arg2_options = "") { if (empty($arg2_optional) { print "not passed"; } else { print "explicit"; } } Or you can go the other route. Jordan "Rodent Of Unusual Size" <Ken.Coar@Golux.Com> wrote in message news:3C8D209D.289F8DAA@Golux.Com... > Rick Emery wrote: > > > > function foo($arg1_required, $arg2_optional="") > > if ($arg2_optional=="") { > > print "not passed"; > > } > > else { > > print "explicit"; > > } > > } > > No, I said 'undef' because I mean 'undefined'. The argument > can have *any* value; I need to know when it has *none*. That > is, there is no magic cookie to which I can set the default that > might not be a valid call value. > -- > #ken P-)} > > Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ > Author, developer, opinionist http://Apache-Server.Com/ > > "Millennium hand and shrimp!"