Passing an array as an argument
| From: | Mauricio Cuenca | Date: | Thu, 14 Mar 2002 16:29:53 +0000 |
| Subject: | Passing an array as an argument | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-88541@lists.php.net to get a copy of this message | ||
Hello,
I've built a function that receives an array as an argument to create an
HTML drop-down list, but when I try to print the list this is all I got:
<select name="my_list">
<option value="Array[0]">Array[1]
<option value="Array[0]">Array[1]
</select>
This is my code:
-------------------
Function TextList($sName, $aOptions)
{
$nCount = Count($aOptions); //Counts the elements of the array
Print(" <select name=\"$sName\">\n");
For ($i = 1; $i <= $nCount; $i++)
{
Print(" <option
value=\"$aOptions[1][0]\">$aOptions[1][1]\n");
}
Print(" </select>\n");
}
*/ Now I build the array */
$my_array = Array( Array(0,0), Array(1,"Enero"), Array(2,"Febrero"),
Array(3,"Marzo"), Array(4,"Abril");
*/ And call the function */
TextList("my_list", $my_array);
I need to know how exaclty can I pass and receive an array as a function
argument. Hope you can help me, TIA.
--
Mauricio Cuenca