Re: Driving me nuts, need one second of your time
| From: | scott furt | Date: | Sat, 16 Mar 2002 21:21:05 +0000 |
| Subject: | Re: Driving me nuts, need one second of your time | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-88779@lists.php.net to get a copy of this message | ||
It's not absurd at all.
What is absurd is that you're coding without
checking for any error conditions :-)
As a rule of thumb, if a function returns a
success flag, check it. it'll immediately
cut out about 90% of all "weird" errors.
cosmin laslau wrote:
<? $query = "SELECT * from mytable"; $result = mysql_db_query("db", $query); while ($myarray = mysql_fetch_array($result)) { $title = $myarray[title]; echo "$title<br>"; } ?> Can someone PLEASE tell me why the coding above gives the following error: Warning: Supplied argument is not a valid MySQL result resource in /var/web/somesite.com/html/index.php on line 5 It's absurd. It's driving me nuts. I'm about to introduce my computer to the pavement 40 feet below. Thanks in advance for whoever sees what I am sure is a glaring and obvious flaw in the coding. I've been looking at it for an hours and just can't get anything from where I'm standing, maybe a different perpective will help. _________________________________________________________________ Get your FREE download of MSN Explorer at http://explorer.msn.com/intl.asp.