Re: regular expression for (NOT 'word')

Try this... it should only print out "Some webpage data" $text = " <script something>script data.</script> Some webpage data <script something>another script data </script> "; print preg_replace('/<script (.*?)></script>(.*?)<\/script>/', '', $text); Ando Saabas wrote:

Ok let me explain my problem further some. I need the regular expression to purify the html page from script tags: I used: $file = eregi_replace("(<script(.*)>.*</script>)", " ", $file); Now this works fine, until theres a webpage like: <script something>script data.</script> Some webpage data <script something>another script data </script> so the regexp above replaces everything between first <script > and last </script> ie the webpage data also. So i thought to change the regexp to something like this: $file = eregi_replace("(<script(.*)>NOT(script)</script>)", " ", $file); where NOT(script) would match everything that contains word script Rick Emery wrote:

the best you can do is: <?php $a = "this has php in the string"; if( ! ereg("php", $a ) ) { print "a: not in string"; } $a = "this has in the string"; if( ! ereg("php", $a ) ) { print "b: not in string"; } ?> -----Original Message----- From: Ando Saabas [mailto:ando.saabas@ttu.ee] Sent: Thursday, March 14, 2002 9:33 AM To: php-general@lists.php.net Subject: [PHP] regular expression for (NOT 'word') how would i build a regular expression in php that would match everything but the given word. For example, match the string only if there isnt a word 'php' in the string. I understand i can list characters i dont want to see in the string: [^php]. but this means there cant be any p or h in the string. And ^(php) checks if the string starts with 'php'. How should i do it? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php