RE: [PHP] Problem with strtotime() and 2002-03-31
| From: | Martin Towell | Date: | Wed, 20 Mar 2002 01:06:19 +0000 |
| Subject: | RE: [PHP] Problem with strtotime() and 2002-03-31 | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-89247@lists.php.net to get a copy of this message | ||
when I tested that code, the adding of 1 day did NOT work, but adding 2 days
DID, sorta, work (it added 1 day)
to "fix" it, I found that I had to add one hour (3600) to the date - maybe
there's something to do with daylight saving??
-----Original Message-----
From: John Clarke [mailto:jclarke@premierstateliner.com.au]
Sent: Wednesday, March 20, 2002 11:40 AM
To: php-general@lists.php.net
Subject: [PHP] Problem with strtotime() and 2002-03-31
I have used the following script successfully for a year now, but have just
found a problem with the date 2002-03-31.
When I add 0 days to this date it returns 2002-03-31. Correct!
When I add 1 day to this date it still returns 2002-03-31. NOT Correct
n I add 2 days to this date it returns 2002-03-31. NOT
correct
So far this is the only date that I havefound a problem with.
Any ideas why this would be happening?
function addDays($date,$nofdays) {
$dd=strtotime($date);
$dd2=$dd + (3600*24*$nofdays);
return date("Y-m-d", $dd2);
}
$nd=addDays("2002-03-31","2");
echo $nd
Regards
John Clarke
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