Re: why doesnt this work???

It still just comes out blank when the vars is wrong.... "R'Twick Niceorgaw" <rtwick@niceorgaw.com> wrote in message news:020501c1d01b$11eb1d00$4176d9d0@careinsite.com... > You need two = signs for comparision not just one . > Also I think you need to enclose the variables in double quote. > > if( $line[1]=="$bruker" and $line[2]=="$passord") echo "hei > $bruker."; > else echo "FEIL"; > > > > -----Original Message----- > > From: chris [mailto:tometerlaks@hotmail.com] > > Sent: Wednesday, March 20, 2002 8:15 AM > > To: php-general@lists.php.net > > Subject: [PHP] why doesnt this work??? > > > > > > this script receives vars "b" and "p" from a form. > > If "b" and "p" matches the echo on IF, then it works just fine. > > The problem is that if the vars dont match the ELSE ECHO > > does not apear... why not? > > > > <? > > $bruker = $HTTP_POST_VARS["b"]; > > $passord = $HTTP_POST_VARS["p"]; > > $hostname = "********"; > > $username = "********"; > > $password = "********"; > > $dbname = "********"; > > MSSQL_CONNECT($hostname,$username,$password); > > mssql_select_db($dbname); > > $query = "select * from medlemmer where bruker = '$bruker' and passord = > > '$passord'"; > > $result = mssql_query( $query ); > > for ($i = 0; $i < mssql_num_rows( $result ); ++$i) > > { > > > > $line = mssql_fetch_row($result); > > if( $line[1]='$bruker' and $line[2]='$passord') echo "hei > $bruker."; > > else echo "FEIL"; > > } > > ?> > > > > -Chris > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > >