RE: [PHP] undefined variable when using if ($var) {}
| From: | Darren Gamble | Date: | Mon, 25 Mar 2002 17:27:35 +0000 |
| Subject: | RE: [PHP] undefined variable when using if ($var) {} | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-90062@lists.php.net to get a copy of this message | ||
Good day.
What is this message that you get, that you don't want?
A cursory glance of the code reveals two "else" statements attached to the
same "if" statement. You should address that.
============================
Darren Gamble
Planner, Regional Services
Shaw Cablesystems GP
630 - 3rd Avenue SW
Calgary, Alberta, Canada
T2P 4L4
(403) 781-4948
-----Original Message-----
From: Martha S [mailto:trippykel@shaw.ca]
Sent: Monday, March 25, 2002 9:44 AM
To: php-general@lists.php.net
Subject: [PHP] undefined variable when using if ($var) {}
I'm rather new to PHP, so this should be fairly easy to answer. I checked
the manual and FAQ already.
I'm using the following code, and I get the following message if $id has
nothing in the var (i have it set to a default of type int, not null in
mysql). Is there a way around this or something I'm missing?
Thanks :)
-- code---
if ($id) {
$result = mysql_query("SELECT * FROM entries WHERE id=$id",$db);
$myrow = mysql_fetch_array($result);
printf("<table border=1><tr>\n");
printf("<tr><td>%s</td></tr>", $myrow["title"]);
printf("<tr><td>%s | ", $myrow["id"]);
printf("%s</td></tr>", $myrow["posted"]);
printf("<tr><td>%s\n</td></tr>", $myrow["post"]);
printf("</table><tr>\n");
printf("<a href=\"$PHP_SELF\">all</a>");
} else {
do {
printf("%s <a href=\"%s?id=%s\">%s</a><br>\n",
$myrow["id"], $PHP_SELF,
$myrow["id"], $myrow["title"], $myrow["post"]);
} while ($myrow = mysql_fetch_array($result));
} else {
// no records to display
echo "Sorry, no records were found!";
}
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php