Re: preg_replace - regex for replace string
| From: | James Taylor | Date: | Wed, 27 Mar 2002 22:53:03 +0000 |
| Subject: | Re: preg_replace - regex for replace string | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-90443@lists.php.net to get a copy of this message | ||
This is just an example. There are some cases where I need the second option
to be a regular expression, the same way that you can do in Perl regex...
On Wednesday 27 March 2002 02:49 pm, you wrote:
> On Wed, 27 Mar 2002, James Taylor wrote:
> > I'm trying to do something to the effect of this for a preg_replace
> > statement:
> >
> > $string = "Hello\n\n\n\n\n\n\nHow are you?\n\n\n\n\n\n\n\nHi";
> > $string = preg_replace("/\n\n/", "/\n/", $string);
> >
> >
> > But, it appears the 'replace' portion of the function doesn't allow for
> > regex. How can I do this so that I CAN have the second statement be
> > regex?
>
> I think you just have your syntax messed up. You don't need delimiters
> around the second argument.
>
> $string = preg_replace("/\n\n/", "\n", $string);
>
> miguel