RE: [PHP] Getting user name in text area
| From: | Rick Emery | Date: | Thu, 28 Mar 2002 23:03:27 +0000 |
| Subject: | RE: [PHP] Getting user name in text area | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-90606@lists.php.net to get a copy of this message | ||
<?php
if($action == "Submit my entry"){
if (!empty($name)){
$enter = "insert into entry (id, user_name) values (NULL,$name)";
mysql_query($enter) or die(mysql_error());
}
exit;
}
$query="SELECT name FROM users WHERE uid=".$session["uid"];
$ret = mysql_query($query) or die(myasql_error());
list($name) = mysql_fetch_array($ret);
?>
<CENTER><table ALIGN="center" WIDTH="80%"><tr>
<td><form ACTION="<?php echo($PHP_SELF);?>" METHOD=post>
<?php
print "<td><br>Username: <input type=\"text\"
value=\"$name\"
name=\"u_name\" size=30></td></tr>\n<tr><td>";
print "<input TYPE=\"submit\" name=\"action\" VALUE=\"Submit my
entry\"><BR><BR>";
?>
</form></td></tr>
</table></CENTER>
-----Original Message-----
From: Jennifer Downey [mailto:jendowney@attbi.com]
Sent: Thursday, March 28, 2002 4:48 PM
To: php-general@lists.php.net
Subject: [PHP] Getting user name in text area
Hi all,
Here is what I have and what I am trying to do.
I would like the user name to be printed in the Username text box but can't
seem to get it there.
I don't want the user to have to type there username in, just click the
submit button and it is entered into the db.
Can anyone show me what I have done wrong?
$query="SELECT name FROM users WHERE uid={$session["uid"]}";
$ret = mysql_query($query);
while(list($name)=
mysql_fetch_row($ret))
print("<BR><BR><BR>$name");
?>
<table ALIGN="center" WIDTH="80%"><tr>
<td><form ACTION="<?php echo($PHP_SELF);?>" METHOD=post>
<?
print "<td><br>Username: <input type=\"text\"
value=\"$name\"
name=\"u_name\" size=30></td></tr><tr><td>";
print "<input TYPE=\"submit\" name=\"action\" VALUE=\"Submit my
entry\"></center><br><br>";
?>
</form></td></tr>
</table>
<?
if($action = "Submit my entry"){
if (!empty($name)){
$enter = "insert into entry (id, user_name) values ('','$u_name')";
mysql_query($enter) or die(mysql_error());
}
}
TIA
Jennifer
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