RE: [PHP] Exit();
| From: | Darren Gamble | Date: | Thu, 04 Apr 2002 15:23:32 +0000 |
| Subject: | RE: [PHP] Exit(); | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-91533@lists.php.net to get a copy of this message | ||
Good day,
As the documentation says, exit() will end your script.
http://www.php.net/manual/en/function.exit.php
Use return() to end a function.
============================
Darren Gamble
Planner, Regional Services
Shaw Cablesystems GP
630 - 3rd Avenue SW
Calgary, Alberta, Canada
T2P 4L4
(403) 781-4948
-----Original Message-----
From: Mauricio Cuenca [mailto:fauro@mindless.com]
Sent: Thursday, April 04, 2002 8:25 AM
To: php-general@lists.php.net
Subject: [PHP] Exit();
Hello,
I'm using recursive functions and call a function from inside another one.
The problem is that when I call the Exit(); function the whole program is
aborted. How can I quit just the current function, not the whole program ?
<example>
Function One()
{
If (!$var) { Exit(); }
}
Function Two();
{
One(); //This line kills the program
Print("Hello"); //This is not printed =(
}
</example>
TIA,
______________________
Mauricio Cuenca
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