Re: What's wrong with the Array? I"m baffled!

> $number = $sumItUp[$name]; > $number++; > $sumItUp[$name] = $number; this could be done easier: $sumItUp[$name]++; :) "Scott Fletcher" <scott@abcoa.com> schrieb im Newsbeitrag news:20020403151803.62904.qmail@pb1.pair.com... > Hi! > > I'm a little baffled on why the array is not working the way I expect it > to. It showed there is something about the array I do not know about. > Well, it's never too late to learn something new. So, here's the code and > see if you can help me out. > > -- clip -- > > $name = "TU4R"; > > if ($sumItUp[$name] == "") { > $sumItUp[$name] = 0; > } else { > //debug > echo "**"; > $number = $sumItUp[$name]; > $number++; > $sumItUp[$name] = $number; > } > echo $sumItUp[$name]."<br>"; > > -- clip -- > > In this case, the if statement never went into else statement when > there's a number like 0, 1, 2, etc. So, what's the heck is happening here? > When the array, "sumItUp[]" was empty then the number "0" was assigned and > it work like a charm. So, when this code is repeated again, the if > statement check the array, "sumItUp[]" and found a number, "0" and it is not > equal to "" as shown in the if statement. So, therefore the else statement > should be executed. But in this case, it never did. I tested it myself to > make sure I wasn't missing something by putting in the php codes, "echo > '**';" and the data, "**" was never spitted out on the webpage. So, > it tell > me that the else statment was never executed. So, the problem had to do > with the data in the array itself. So, can anyone help me out? Thanks a > million!!!!!! > > Scott > >