RE: [PHP] regexp for ' replacement

regexp is not what you need then You will require a character-by-character search/replace or try: <?php $q = "'here's to you'"; print "\$q= $q\n"; $a = addslashes($q); print "\$a= $a\n"; $z = ereg_replace("\\\'(.*)\\\'","'\\1'",$a); print "\$z= $z\n"; ?> which produces: $q= 'here's to you' $a= \'here\'s to you\' $z= 'here\'s to you' -----Original Message----- From: Thalis A. Kalfigopoulos [mailto:thalis@cs.pitt.edu] Sent: Friday, April 05, 2002 11:35 AM To: Rick Emery Cc: php-general@lists.php.net Subject: RE: [PHP] regexp for ' replacement Nop. I don't want to affect the first and last ' of every line. On Fri, 5 Apr 2002, Rick Emery wrote: > addslashes($textline) > > -----Original Message----- > From: Thalis A. Kalfigopoulos [mailto:thalis@cs.pitt.edu] > Sent: Friday, April 05, 2002 10:54 AM > To: php-general@lists.php.net > Subject: [PHP] regexp for ' replacement > > > Yet another regexpr question. > If I have as part of a text: > ...and then 'the quick brown fox jumped over the lazy dog's piano'... > > How can I substitute the single quote in "dog's" with say \' > I want to aply a substitution for only the single quote that is between two > single quotes and leave the rest of the text in between the same. > > Make sense for regexpr usage? > > TIA, > thalis > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >