Re: Outputting Array Values

From: Date: Tue, 09 Apr 2002 14:43:58 +0000
Subject: Re: Outputting Array Values
References: 1  Groups: php.general 
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On Tue, 9 Apr 2002, Martin Clifford wrote: > echo "<tr><td>Item " . ($n + 1) . " is > $List[$n].</td></tr>"; > > It successfully prints out the following: > > Item Number 1 is . > > I just don't understand why it doesn't print out each value in the > array... any help would be VERY appreciated! Also, please CC me on any > replies, as I'm subscribed to the digest! Thanks! If you put an array dereference inside a literal string, you have to surround the whole assembly with curly braces, thusly: echo "<tr><td>Item " . ($n + 1) . " is {$List[$n]}.</td></tr>"; miguel

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