RE: [PHP] IF statement problems

From: Date: Mon, 31 Jul 2000 18:42:11 +0000
Subject: RE: [PHP] IF statement problems
Groups: php.general 
Request: Send a blank email to php-general+get-9231@lists.php.net to get a copy of this message
Sorry about that, yes in the example I gave I'm missing the semicolon. But in the script it is there. Thanks, -Paul -----Original Message----- From: Sam Masiello [mailto:smasiello@chekinc.com] Sent: Monday, July 31, 2000 11:42 AM To: Paul Hawkins; php-general@lists.php.net Subject: RE: [PHP] IF statement problems You are missing a semicolon after $value=4 HTH Sam Masiello System Analyst Chek.Com (716) 853-1362 x289 smasiello@chekinc.com -----Original Message----- From: Paul Hawkins [mailto:phawkins@californiasteel.com] Sent: Monday, July 31, 2000 2:37 PM To: php-general@lists.php.net Subject: [PHP] IF statement problems I'm having a bit of trouble with an if statement generated from a few pull-down menus on a form. The two pull-downs set the variables $vname and $div. Based on the combination of their values I need to set a separate variable $value. The following IF statement works fine until I include the last if statement. IF the last IF statement is in the script it gets evaluated as true no matter what is selected on the form. Here is the code: if ($choice) { if (($vname==1) AND ($div==1)) { $value=1; } if (($vname==1) AND ($div!=1)) { $value=2; } if (($vname!=1) AND ($div==1)) { $value=3; } if (($vname!=1) AND ($div!=2)) { //bad if statement $value=4 } } Thanks, Paul Hawkins -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net

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