Re: popen(); problem, the function don`t finds the command......
| From: | Barry C. Hawkins | Date: | Thu, 11 Apr 2002 14:09:19 +0000 |
| Subject: | Re: popen(); problem, the function don`t finds the command...... | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-92573@lists.php.net to get a copy of this message | ||
Hermann,
Maybe change:
$saslpasswd = "/usr/sbin/saslpasswd -p $username";
to:
$saslpasswd = "/usr/sbin/saslpasswd -p " . $username;
I assume $username is being assigned somewhere.
Regards,
--
Barry C. Hawkins
Systems Consultant
All Things Computed
barry.hawkins@allthingscomputed.com
On Thu, 11 Apr 2002 14:53:50 +0000 Hermann Bier <kpot@gmx.net> wrote:
Hi!!
i`ve wrote a little script to run under shell, so this script:
#!/usr/bin/php
$saslpasswd = "/usr/sbin/saslpasswd -p $username";
$saslproc = popen($saslpasswd,"w");
fputs($saslproc, $passwd);
pclose($saslproc);
php-parser gives me the following as output:
#
sh: /saslpasswd: No such file or directory
#
what i`m doing wrong??
please help.
bye
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