Re: Image functions

You won't get very far if you aren't outputting an image to the browser using ImageJpeg(), etc. Matt Matthew J Gray UWRF - Information Technology Services Matthew.J.Gray@uwrf.edu Gerard Samuel wrote: > Im trying to modify a poll script to not use the hard coded image files > and use php's image functions. > On the file that will be outputing the poll graphics, I tried at the top > of the page -> > header("Content-type: image/png"); > and > header("Content-type: image/jpeg"); > > For some reason, when the page is viewed, the only thing that gets > output to the browser is the url of the page.... > > I tried using one of the examples on php.net image create routines and > its still doing the same thing.. > > Here is a snip > > <?php > > /* > * THIS HAS TO GO HERE FOR THE IMAGE BARS > */ > header("Content-type: image/jpeg"); > > $pollID = $HTTP_POST_VARS['pollID']; > $voteID = $HTTP_POST_VARS['voteID']; > > <------snip---------> > > If I comment out the header call, Im back to normal... > Im running PHP 4.1.2 with GD support > Any thoughts > Thanks