Re: Destroy a session var passed as an argument

On Wednesday, April 24, 2002, at 02:59 PM, Julio Nobrega Trabalhando wrote:

I have a simple function that returns a message: function showError ($mensagem) {

    return '<div class="erro">' . $mensagem . '</div>';

} And this is how I use it: if (isset($_SESSION['forum']['error']['insert'])) {

    echo showError($_SESSION['forum']['error']['insert']));

} But I want that when the function is used the session variable is destroyed. A simple unset($mensagem) inside showError() gives me back this: Warning: Undefined variable: mensagem in c:\www\lib\sistema\formularios\formularios.inc.php on line 92

The problem is that there is no variable called $mensagem in your function. You are using a reference to something else with the name $mensagem, but you are not passing the value by reference -- try this: function showError(&$mensagem) // note the '&' before $mensagem { return '<div class="erro">' . $mensagem . '</div>'; } And let me know if that works or doesn't work. (It's kind of a hunch, hard to tell from your code if it will work.) Erik ---- Erik Price Web Developer Temp Media Lab, H.H. Brown pricee@hhbrown.com