RE: [PHP] build array dinamicaly

Be careful - I fell into this trap when I first started doing this sort of thing. This code will produce an extra element on your array with value logical false. You need to do ... While ($array = mysql_fetch_array($result)) $myarray[] = $array; ... to avoid this Tim Ward Internet Chess www.chessish.com <http://www.chessish.com> ---------- From: Richard Emery [SMTP:remery@emeryloftus.com] Sent: 29 April 2002 21:57 To: Rodrigo Peres; PHP Subject: Re: [PHP] build array dinamicaly $query = "SELECT name,address FROM tbl"; $result = mysql_query($query); while($myarray[] = mysql_fetch_array($result); ----- Original Message ----- From: Rodrigo Peres <rperes@mac.com> To: PHP <php-general@lists.php.net> Sent: Monday, April 29, 2002 9:20 AM Subject: [PHP] build array dinamicaly Hi list, I want to buil an multidimensional array with the results of Mysql, but I don't know how to do it. What I need is: "SELECT name,adress from tbl_....." array name will receive the names array adress will receive the adresses and array clientes will contain both, so when i try to access i will have something like $cliente['nome'][0] or $clientes['adress'][1] and so on. Someone can help??? Thank's in advace Rodrigo Peres -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php