Re: Help php MySql link
| From: | George Nicolae | Date: | Fri, 03 May 2002 18:35:30 +0000 |
| Subject: | Re: Help php MySql link | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-95952@lists.php.net to get a copy of this message | ||
$db = ("localhost","databasename","databasepassword");
mysql_select_db("your name?",$db);
$result = mysql_query("select column1, column2 from domain", $db);
while ($myrow=mysql_fetch_array($result))
echo $myrow["column1"]." - ".$myrow["column2"]."<br>";
--
Best regards,
George Nicolae
IT Manager
___________________
PaginiWeb.com - Professional Web Design
www.PaginiWeb.com
"Rodrigo" <tagzero@tagzero.com> wrote in message
news:000401c1f2cf$28b83f00$d86bbbac@rodirgo...
> Hi guys, what I need is how to make the link between the php and the
> Database.
>
> Is this the code for it? ro something like that? Help me guys...
>
> If you could tell me what each command line do I'd appreciate it, cause
> I got almost all from a friend, but is incomplete.
>
> The code follows this message.
>
>
> $db = ("localhost","databasename","databasepassword");
> mysql_select_db("your name?",$db);
> $result = mysql_query("select column1, column2 from domain", $db);
> echo "column 1 - column 2";
>
>