Re: Fw: Confirm Remote File exists !

On 8 May 2002 at 17:01, John Fishworld wrote: > I've got a form where people can enter a link into ! > > What's the best and quickest way of confirming if the link exists ! > Just use fpassthru and see if you get an error ? > Or has anyone got any better suggestions ?? I wrote the following function a while back. I've only ever used it with http urls so I don't know if it works properly for other types. Let me know if it's useful. function RemoteFileExists($url, $referer = "") { $url_parts = parse_url($url); if ($url_parts["scheme"] != "http" && $url_parts["scheme"] != "https" && $url_parts["scheme"] != "ftp") { return TRUE; } $ch = curl_init(); $urltoget = $url_parts["scheme"]."://".$url_parts["host"].$url_parts["path"]; if (isset($url_parts["query"])) $urltoget .= "?".$urltoget["query"]; curl_setopt ($ch, CURLOPT_URL, $urltoget); if ($url_parts["scheme"] == "http" || $url_parts["scheme"] == "https") { curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch, CURLOPT_NOBODY, 1); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); if (strlen($referer) > 0) curl_setopt($ch, CURLOPT_REFERER, $referer); } curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $reply = curl_exec($ch); curl_close($ch); if ($url_parts["scheme"] == "http" || $url_parts["scheme"] == "https") { $result = explode(" ", $reply); $reply = ($result[1] == "200"); } return $reply; } -- Stuart