RE: [PHP] Listing the contents of a directory in an array
| From: | Jared Boelens | Date: | Fri, 17 May 2002 13:28:17 +0000 |
| Subject: | RE: [PHP] Listing the contents of a directory in an array | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-98077@lists.php.net to get a copy of this message | ||
I actaully had to do that yesterday, here is the code i used.
$path = "/foo/bar";
$myArray = $array();
$dir = opendir($path);
while($file = readdir($dir)) {
// if(!ereg("^\.", $file) {
$myArray[count($myArray)] = $file;
// }
}
closedir($dir);
If you want to exclude the always present "." and ".." directories just
uncomment those two lines.
-Jared
-----Original Message-----
From: webmaster@tececo.com [mailto:webmaster@tececo.com]
Sent: Friday, May 17, 2002 8:31 AM
To: php-general@lists.php.net
Subject: [PHP] Listing the contents of a directory in an array
I am a newbie so be kind
I have looked into the manual about directory functions etc.
I want to return all the files from a directory into a array.
Could some one give me a few pointers or something?
I keep getting confused but I have used google and the manual.
I can find functions but I am not sure how I can list the files into an
array.
Thanks in advance,
JJ Harrison
webmaster@tececo.com
www.tececo.com