RE: [PHP] Feelin' dumb...

Makes sense. Thanks! Now... I have this little problem: if ($num_pages >= 2) { for ($i=1; $i<=$num_pages; $i++) { $number = ($i * 20) + 1; $page = $i+1; printf("| <a href=\"test.php?page=%s\">Page %s</a> | ", $number, $page); } } I want $page to be $i + 1, but when I do $page = $i+1;, $i somehow gets evaluated into the for() loop and an additional iteration is completed. So basically if I do it this way, I get I'll get 1, 21, 41, when really only 1 and 21 are valid. If I put in $page = $i++; it works correctly, but $i is 1 when I want it to be two. If I take out $page = and put in $i where $page is in the printf() statement, I get the extra iteration again. Any ideas? -----Original Message----- From: Craig Vincent [mailto:2bunnyhop@rogers.com] Sent: Friday, May 17, 2002 7:56 PM To: Jason Soza; php-general@lists.php.net Subject: RE: [PHP] Feelin' dumb... > I wonder why the other suggestions weren't working. They seemed logical > enough, I even tried variations of your suggestion, first I tried: > > for ($i=1; $i<=$num_pages; $number = $i + 20) {} > for ($i=1; $i<=$num_pages;) { $number = $i + 20; } The problem with these two statements was that the loop would be indefinate. Without the third option $i is never incremented (unless you manually increment it from within the loop). So with your examples $i would always be 1 and would therefore always be <= $num_pages unless $num_pages was zero or negative. Sincerely, Craig Vincent -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php