Variable won't work in function, even when I global it?
| From: | Leif K-Brooks | Date: | Mon, 20 May 2002 05:23:12 +0000 |
| Subject: | Variable won't work in function, even when I global it? | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-98416@lists.php.net to get a copy of this message | ||
On my website, I open my header (and footer) file with fileopen and then eval() it. I know I should include them, but I knew nothing about php when I did this. Anyway, I'm working on "groups" for my website. They will be a kind of club. At the top of every group page, I include a group function file. Among those functions is one that checks if the user trying to go to the group is a member of it. If not, it gives them an error message and exits. It is also supposed to eval() the footer before exiting. My code is as follows:
function checkmember(){
global $groupid;
global $userinfo;
global $footertext;
if($groupid != $userinfo['groupid']){
print "<b>Error:</b> you're not a member of this group.";
eval($footertext);
exit;
}
return;
}
The thing is, it doesn't seem to eval() the footer. I've even tried getting $footertext out of the $GLOBALS array. I have also tried printing $footertext to make sure it wasn't a problem with evel(). Nothing has worked. When I did isset() on $GLOBALS['footertext'], it worked however. Thanks to anybody who can help.