RE: [PHP] inspirational

Why don't you try something like this...do a system call to pwd and strip out the portion of the url that you know is the upper directory. Then you can exchange that for the http://www.site.com/ and then add the additional directories to the end and call the script name...there might not be a function that does all this, however, you can try to work around it.... Thanks, Ray Hunter -----Original Message----- From: jtjohnston [mailto:taylorjo@collegesherbrooke.qc.ca] Sent: Saturday, May 25, 2002 11:39 PM To: php-general@lists.php.net Subject: [PHP] inspirational I want to detect the url my .php lies in. This is over kill and BS: $myurlvar = "http://".$SERVER_NAME.parse($SCRIPT_NAME); How do I get "http://foo.com/dir1/dir2/dir3/". There seems to be nothing in phpinfo() that will give me a full url to play with. Flame me if you will, but I browsed TFM and found nothing inspirational. Looked at phpinfo() too and got discouraged. I need a full url. John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php