Re: PHP datatype vs Oracle Varchar2

On Thu, Jul 26, 2001 at 07:27:07PM -0500, Victoria Zhou wrote: > Here is a description of the testcase for the problem: > > Oracle: > Create table Mytable ( > Username varchar2(20), > Passwd varchar2(20), > Usertype varchar2(50)) > > Insert into Mytable (Username, Passwd, Usertype) > values('tester1','tester1','Operator'); > > PHP: > $sql = "select * from Mytable where Username='tester1'"; > $sql_statement = OCIParse($conn, $sql) or die ("Couldn't parse statement"); > OCIExecute($sql_statement) or die ("Couldn't execute query"); > > > Problem: > The string comaparison in the $sql (Username='tester1') is never true, > because Username is a variable length string and 'tester1' is considered as > a fixed length string. wrong - that should not be the case. > > I don't have the flexibility to change VARCHAR2 to CHAR in order to make > this work, because a fixed length string will cause a lot of trouble for > string comparisons for other code in the program. > > Thanks for your help! i did the same thing (i hope) and it woorsk for me. i see no reason why it shouldn't work. there is _no_ reason to switch to from varchar to char! please try to do the _same_ select-statement in sqlplus - tc > > Victoria > > > > > > -----Original Message----- > > From: Thies C. Arntzen [mailto:thies@thieso.net] > > Sent: Thursday, July 26, 2001 6:10 PM > > To: Victoria Zhou > > Cc: php-install@lists.php.net; php_install@lists.php.net > > Subject: Re: [PHP-INST] PHP datatype vs Oracle Varchar2 > > > > > > On Thu, Jul 26, 2001 at 05:08:42PM -0500, Victoria Zhou wrote: > > > > > > Hi, > > > > > > The comparison between Oracle VARCHAR2 and a PHP string doesn't seems to > > > work. Detail as follows: > > > > > > I have one PHP variable and one Oracle column: > > > . $form_user_id: a PHP string obtained from web form input, > > such as 'user1'. > > > . Username: an oracle table column of type VARCHAR2(20). > > > > > > The following sql statement failed: > > > "select * from mytable where Username='$form_user_id'" > > > > > > It failed because Username has a strlen of 20, where $form_user_id has a > > > strlen of 5. If I changed the Username from VARCHAR2(20) to > > CHAR(20), then > > > this sql worked fine. But I think with Oracle VARCHAR2, the strlen of > > > Username in this case should be 5 instead of 20. > > > > you must be doing something wrong here;-) > > > > please try to create a _tiny_ testcase (< 20 lines) and post > > it to the list, i'm sure you're overseeing something > > important. > > > > tc > > > > >