stuck display ......

hi guyx i ve a lil problem i run this query n get a result set $query = "SELECT lang_id,strng_id, strng FROM strngx where pg_id = 6 and lang_id = '$lang_id '"; $query_result_handle = mysql_query ($query) or die ('qry failed ! DA tbl must xixt in DA db specifyd bov ....'); exe and store it in $row for( $v=1; $v < mysql_num_rows($query_result_handle); $v++) {

    $row = mysql_fetch_row($query_result_handle);
    $str[ $row[0] ][ $row[1] ] = $row;

} alls well but i want to get a single record displayed when i do echo($row[2]."<br>"); i get all the records in $row[2] but i want jst 1 what should i do ????? how should i go about it .... ????? plx plx help m stuck ... :( thnx a million ..... billion stuck .... toby .... _________________________________________________________________ MSN Photos is the easiest way to share and print your photos: http://photos.msn.com/support/worldwide.aspx