Re: PHP5: expected __METHOD__ behavior

Daniel J Cain Jr. wrote:

I am by no means an expert with OOP, so if this is a blatantly retarded question please excuse my ignorance. Given this code: <?php class A {

    function foo()
    {
        echo __METHOD__;
    }

} class B {

    function bar()
    {
        // blah
    }

} $instance = B::foo(); ?> output is "A::foo". Is this correct? I would expect (want maybe :) ) to see output as "B::foo". If you need more information please let me know. TIA -dan Hi,

this "constant" like the others is resolved on compile time. Another example is __CLASS__: php -r 'class a{ function c() {var_dump(__CLASS__);}}class b extends a{};$a=new b();$a->c();' dumps : string(1) "a" __METHOD__ is resolved as __CLASS__.'::'.__FUNCTION__ IMO the current behaviour is the normal since works like the C preprocessor doing substitutions before compile (PHP does it while compiling). You can get what you wanted with this : echo get_class($this).'::'.__FUNCTION__ (when there is an instance of the class) but AFAIK in your case with static calls there is no solution. Cheers, Andrey