Re: Object Type Casting Reloaded

I think we would be talking about typed variables at that point. ( something you can do with PHP 7.4 http://github.com/azjezz/typed ) even though as is used with foreach, i don't think it would be an issue to use it for something else, but i think i will leave that to someone who's more familiar with the PHP parser than me. Cheers. Sent with ProtonMail Secure Email. ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐ On Tuesday, April 23, 2019 1:43 AM, Stephen Reay <php-lists@koalephant.com> wrote: > > On 23 Apr 2019, at 06:30, azjezz azjezz@protonmail.com wrote: > > Hello Ben. > > yes, i have made a gist with a simple example to show the as� > > see : > > https://gist.github.com/azjezz/03955ff2b009f1ced22ce68c9a862847 > > Sent with ProtonMail Secure Email. > > ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐ > > > > > On Monday, April 22, 2019 11:50 PM, Benjamin Morel benjamin.morel@gmail.com wrote: > > > Hi Azjezz, thanks for jumping in! > > > > > > > I have been using HackLang for quite a while now and i believe they have a > > > > better solution for this, and it would awesome to see it in PHP, the > > > > as operator. > > > > > > If I understand correctly, as is an operator that > > > performs type checks but never casts like () does. > > > This looks like a serious candidate for an alternative syntax to the one I proposed! > > > > > > - Ben > > I like the idea but I find the syntax (both suggestions) less than great, given that there’s > already “ensure a type” syntax, and both suggestions are already used for other things (casting > and foreach) > > Is there some reason (eg ambiguities) a type can’t just be placed before a variable to ensure > a type, similar to a function parameter or typed property? > > Eg > > string $foo = 'bar'; > array $bar = getBar(); > foreach($bar as int $k => string $v) {...} > > Cheers > > Stephen