Re: [RFC] Namespace-scoped declares, again

From: Date: Tue, 13 Aug 2019 17:05:00 +0000
Subject: Re: [RFC] Namespace-scoped declares, again
References: 1 2 3 4  Groups: php.internals 
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On 13/08/2019 12:01, Mark Randall wrote:
On 13/08/2019 10:02, Rowan Collins wrote:
I really like this approach. It allows a package definition file to exist, without either the language or the header of each file having to define its location.
# # File: /lib/company/project1/a/b/MyClass.php # <?php   declare_import(company[:label]);   namespace company/project1/a/b;   ... # # File: /lib/company/__nsmeta.php # <?php   namespace company;   namespace_declare [:label] {
    strict_types=1;
    strict_operators=1;
    upgrade_errors_to_exceptions=E_ALL;
  }   final class __nsmeta {
    /* does nothing except be findable by the autoloader */
    /* and defaults to private constructor so it can't be used */
  }
This seems to be more complicated than Nicolas's version, and involve much more special magic, like the name __nsmeta, and the class that does nothing. I'm also not clear on how you're picturing the relationship between namespaces and packages. The way I understood the suggestion, you'd end up with something more like this, which feels much simpler and cleaner: # # File: /lib/company/project1/a/b/MyClass.php # <?php declare(package=company/project1); // or with a new keyword package company/project1; namespace company/project1/a/b; ... # # File: /lib/company/project1.php # <?php namespace company; class project1 extends \PHP\Package {
    public function getParserDirectives() {
        return [
            'strict_types' => 1,
            'strict_operators' => 1,
            'upgrade_errors_to_exceptions' => E_ALL
        ];
     }
} Regards, -- Rowan Collins [IMSoP]

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