[RFC] throw expression

Hi everybody! Yesterday I stumbled upon this Tweet by Nikita: https://twitter.com/nikita_ppv/status/1240309838950866946 It answered why this seemingly correct block of code doesn't work:     fn() => throw new Exception('nope'); The answer is rather simple. throw is a statement, not an expression. However, arrow functions only allow a single expression as their bodies. The obvious solution is to convert throw to an expression. This would also allow for the following:     $value = $nullableValue ?? throw new InvalidArgumentException();     $value = $falsableValue ?: throw new InvalidArgumentException(); At the moment this is generally done by moving the throw into a function:     function throwInvalidArgumentException() {         throw new InvalidArgumentException();     }     $value = $nullableValue ?? throwInvalidArgumentException(); or of course by just using an if statement:     if ($nullableValue === null) {         throw new InvalidArgumentException();     } Neither of those are bad. The new syntax is just slightly more concise. An implementation of the change can be found here: https://github.com/php/php-src/pull/5279 It's also noteworthy that the same feature has semi-recently been added to C# 7.0: https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/throw#the-throw-expression This has been proposed a handful of times in the internals mailing list but never extensively discussed: https://externals.io/message/49569 (2010) https://externals.io/message/15301 (2005) https://externals.io/message/10553 (2004) Let me know what you think! Also, to actually create the RFC I need RFC karma. Can someone grant me those privileges? My username is ilijatovilo. Thank you!