Re: Chaining __set and __get in an expression

Hello Curt, From http://us2.php.net/manual/en/language.operators.assignment.php "The value of an assignment expression is the value assigned. That is, the value of "$a = 3" is 3." I take this to mean that ($foo->a = 'bar') will always return 'bar' and that is a core feature of the language. Remember that $foo->a is the left hand operand, and is only receiving the value. It is the = operator that returns the value of the expression. It may also be worth noting that the Associativity of the = operator is "Right". -- Best regards, Jason mailto:jason@ionzoft.com Tuesday, July 20, 2004, 12:26:46 AM, you wrote: CZ> Given the class definition: CZ> <?php CZ> class Caller { CZ> private $x = array('a' => false); CZ> function __set($name, $value) { CZ> echo "setting\n"; CZ> $this->x[$name] = 'foo'; // intentially ignore value CZ> } CZ> function __get($name) { CZ> echo "getting\n"; CZ> return $this->x[$name]; CZ> } CZ> } CZ> $foo = new Caller(); $b = $foo->>a = 'bar'; CZ> echo "b is " . $b . "\n"; CZ> /* output: CZ> setting CZ> b is bar CZ> */ ?>> CZ> I sort of expected both __set and __get to be called. Is it CZ> concievable to have them both called? CZ> The other alternative If possible, is allowing a return value CZ> from __set() and using that value for the rest of the expression. CZ> Curt CZ> -- CZ> First, let me assure you that this is not one of those shady pyramid schemes CZ> you've been hearing about. No, sir. Our model is the trapezoid!