Re: [RFC] Partial Function Application, take 2

From: Date: Fri, 11 Jun 2021 11:01:43 +0000
Subject: Re: [RFC] Partial Function Application, take 2
References: 1  Groups: php.internals 
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Sorry, me again :s I have tested the examples from https://wiki.php.net/rfc/partial_function_application on https://3v4l.org/#focus=rfc.partials and several of them currently give an error: - Ex 10: on the line $c = stuff(?, ?, f: 3.5, ..., p: $point); => Fatal error: Named arguments must come after all place holders (typo I guess, $c = stuff(?, ?, ..., f: 3.5, p: $point); is OK) - (Ex 11: no error but a typo: 'hi' vs 'foo') - Ex 16: for the last call (four(..., d: 4, a: 1))(2, 3); => Fatal error: Uncaught ArgumentCountError: four(): Argument #2 ($b) not passed (on the function definition line) ((four(..., d: 4, a: 1))(2, 3, 5, 6); idem, but (four(..., d: 4, a: 1))(b: 2, c: 3); throws an "Unknown named parameter $b" Error on the call line) (weird) - func_get_args() and friends: one the last line $f(1, 2); (after `$f = f(?);`) => Fatal error: Uncaught Error: too many arguments for application of f, 2 given and a maximum of 1 expected (can make sense, e.g. https://externals.io/message/114532#114554 ) - (Callable reference: no error but a typo: $f vs $foo) - Optimizations: on the line $boo = $baz(4, ...); => Fatal error: Uncaught Error: too many arguments and or place holders for application of Closure::__invoke, 1 given and a maximum of 0 expected ($boo = $baz(?); throws the same error, but $boo = $baz(4); throws a "not enough arguments for implementation of foo, 4 given and exactly 5 expected" Error, and $boo = $baz(...); makes the subsequent $boo(5); throw a "not enough arguments ..." Error) (weird, looks like $bar = $foo(2, ...); and/or $baz = $bar(3, ...); dropped too many params) Regards, -- Guilliam Xavier

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