Re: [RFC brainstorm] Approximately equals operator

I love April Fools jokes. Yes, and let's add the null coalescing increment and decrement operators: $foo??++ and $bar??-- . I want to ensure that an undeclared or null variable defaults to 0 before becoming 1 or -1 without needing to manually instantiate the variable as 0. Pfft. --- Anyhow, why wouldn't rounding precision be decided by the precision of the float/integer with the lesser precision? 1. 1.55 ~= 1.5499 // true (because rounding 1.5499 to 2 decimal places is 1.55) 2. 3.1415 ~= 3.141 // false (because rounding 3.1415 to three decimal places is 3.142) 3. 1000 ~= 999.50000001 // true (rounding to integer comparison) mickmackusa