Re: why is '01' == '1.'?

On 12/14/05, Greg Beaver <greg@chiaraquartet.net> wrote: > In this case, a string is explicitly being compared to a string, and yet > both are being converted to an int prior to comparison. I can > understand that implicit type conversion is needed when comparing > strings to ints, but this can be dangerous. phpDocumentor, for instance > uses this code: > > if (in_array(substr($ltrimword, 0, 2), array('1.', '0.'))) Perhaps if (preg_match('/^[10]\./',$ltrimword)) would be both more concise and express your intent better? Regards, Jason http://blog.casey-sweat.us/