Re: Re: access to variables

On 4/24/07, Ci <ciptok@gmail.com> wrote:

I tried to use smth like that: zval *data = NULL; zend_hash_find(Z_ARRVAL_P(PG(http_globals)[TRACK_VARS_SERVER]),

       "DOCUMENT ROOT", sizeof("DOCUMENT ROOT"), &data);

strcpy(buffer, Z_STRVAL_P(data); Then I write the buffer to file, but I don't get correct variable. I'm working with php-5.2.1. Am I in a good way to solve my problem? Regards, Ci

Ok, i don't know a lot about the core of PHP, but i do know the C language. First of all, i don't see you declaring buffer somewhere, i guess you did it without showing, or that it is in the core. But if it isn't both, you should do :) Also note that buffer should be declared as char *buffer to be able to use the strcpy function on it. Second, when you're using the strcpy function, you have 2 '(' used, and only one ')' I guess this is a type here. (else it would return error on compilation i guess) Third, the function strcpy also has a return value. It should be returned to a pointer to the string where it is copied to. so it would become: buffer = strcpy(buffer,Z_STRVAL_P(data)); If all above noted is correct, then it is a problem with your zend_hash_find function, but as i noted already, i don't know a lot of the PHP core, so i can't help further with it. Tijnema