Re: Question about zend_hash.c, UPDATE_DATA macro

From: Date: Tue, 29 Jul 2003 16:11:47 +0000
Subject: Re: Question about zend_hash.c, UPDATE_DATA macro
References: 1  Groups: php.internals 
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Just to make sure I understand what you're asking, are your first and second updates of data with different sizes? Andi At 02:50 PM 7/29/2003 +0300, Vesselin Atanasov wrote:
Hello. In PHP5, file zend_hash.c there is a macro #define UPDATE_DATA(ht, p, pData, nDataSize) \
        if (nDataSize == sizeof(void*))
{ \
                if (!(p)->pDataPtr)
{ \
                        pefree((p)->pData, (ht)->persistent);
\
                }
\
                memcpy(&(p)->pDataPtr, pData, sizeof(void *));
\
                (p)->pData = &(p)->pDataPtr;
\
        } else
{ \
                if ((p)->pDataPtr)
{ \
                        (p)->pData = (void *) pemalloc(nDataSize,
(ht)->persistent);    \
                        (p)->pDataPtr=NULL;
\
                }
\
                memcpy((p)->pData, pData, nDataSize);
\
        }
The macro is used to update a hash table element in zend_hash_add_or_update(). But it seems to me that if p->pData already points to a data block that hash size != sizeof (void *), and the macro is called to update the hash element with another block that has size != sizeof (void *), then the data block pointed at by p->pData will not be reallocated and the last memcpy() call will overwrite the old data block with the new data. This could possibly lead to memory corruption if the new block is bigger than the old block. Could any of the PHP developers comment on this? -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php


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