Re: Private properties, Inheritance, Reflection (5.3)

For what it matters, the same thing in Java returns the expected result: Class clazz = Foo.class; Field fooProp = clazz.getDeclaredField("foo"); fooProp.setAccessible(true); Bar bar = new Bar(); String value = (String)fooProp.get(bar); System.out.println(value); So is this a bug or some weird behavior I just don't understand yet? Roman On Apr 4, 2009, at 7:34 AM, Roman Borschel wrote:

Hi, On Apr 4, 2009, at 1:53 AM, Johannes Schlüter wrote:

On Fri, 2009-04-03 at 22:37 +0200, Roman Borschel wrote:

Given the following simple classes class Foo { private $foo = 'value'; public function getFoo() { return $this->foo; } } class Bar extends Foo {} Obviously, given an instance of Bar, say $bar, $bar->getFoo() returns 'value'. Now the question: How do I get at this value using reflection, given an instance of Bar?

class Foo { private $foo = "value"; } class Bar extends Foo {} $f = new Foo; // we have to know the context, as there might be multiple foo properties $r = new ReflectionProperty("Foo", "foo"); $r->setAccessible(true); var_dump($r->getValue($f)); works for me. johannes

Thanks for your answer. Yes, this works, but here $f is an instance of Foo, not Bar. When you make it an instance of Bar you get NULL. I think this is not correct, is it? Given that we have a ReflectionProperty of class Foo at hand, from my understanding it should look at an instance of Bar as a Foo and return the value. Am I missing something? Regards Roman -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php