Re: Closure/lambda semantic comparaison
| From: | Ionut G. Stan | Date: | Mon, 01 Mar 2010 22:08:18 +0000 |
| Subject: | Re: Closure/lambda semantic comparaison | ||
| References: | 1 | Groups: | php.internals |
| Request: | Send a blank email to internals+get-47075@lists.php.net to get a copy of this message | ||
In my opinion this is consistent with the fact that PHP has no block-scoped variables. The situation is similar with the one in JavaScript.
In JavaScript the problem has been solved by Mozilla with so-called let definitions[1], which are block-scoped.
1: https://developer.mozilla.org/en/New_in_JavaScript_1.7#Block_scope_with_let
On 3/1/10 2:33 PM, mathieu.suen wrote:
Hi, I am proposing a comparison between PHP closure with lisp one. First thing to compare is how scope are capture: Suppose I want to create a function that add. The common idiom to do it in lisp is: (defun adder (x) #'(lambda (y) (+ x y))) Then if I want the add3 method you can do: (setf (symbol-function 'add3) (adder 3)) (add3 4) => 7 Now let reproduce that in php: $adder = function ($x) {return function ($y) use($x) {return $y + $x;};}; $add3 = $adder(3); echo $add3(4); => 7 Every thing is fine but let change the adder into a counter : In lisp you could do: (let ((sum 0)) (defun counter () (setf sum (1+ sum)))) (counter) => 1 (counter) => 2 (counter) => 3 ... In other to have the same behavior in PHP you first need to transform the let into a lambda which make no difference in lisp: (funcall #'(lambda (sum) (defun counter () (setf sum (1+ sum)))) 0) Now we are ready to do it in PHP. $createCounter = function ($sum) { return function () use ($sum) {return ++$sum;};}; $counter = $createCounter(0); $counter(); => 1 $counter(); => 1 $counter(); => 1 ... So that's not the expected behavior. In oder to have the expected behavior you need to add & in front of $sum. But & is kind of evil since it mimics dynamic scoping: $array = array(1, 2, 3); foreach($array as $pos) { $adders[] = function ($x) use (&$pos) { return $pos+ $x;}; } foreach($adders as $addIt) { echo $addIt(5); } Thanks for your attention -- Mathieu Suen-- Ionut G. Stan I'm under construction | http://blog.igstan.ro/